Factor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)Learn about expand using our free math solver with stepbystep solutionsSolve for x and y 3/x 1/y 9 = 0, 2/x 3/y = 53/x1/y=9 2/x3/y=5 by substitution method3/x1/y=9 2/x3/y=5 by elimination method3/x1/y9=0 2/x3/y=5
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